What is the limit as t approaches-2 of sqrt(8+t^3) ?

The limit as t approaches-2 of sqrt(8+t^3) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as t approaches-2 of sqrt(8+t^3)

t \to - 2 lim (8 + t^{3})

0

Solution steps

t \to - 2 lim (8 + t^{3})

Plug in the value

t = - 2

= 8 + (- 2)^{3}

Simplify

8 + (- 2)^{3} : 0

= 0

cos (arcsin (x))

y^{^{'}} = (t + y) 2 - 1, y (1) = 6

\frac{2}{x ^{3}}

f (x) = 2 sin^{2} (π x), at x = \frac{3}{4}

What is the limit as t approaches-2 of sqrt(8+t^3) ?
The limit as t approaches-2 of sqrt(8+t^3) is 0