What is the tangent of f(x)=2sin^2(pix),\at x= 3/4 ?

The tangent of f(x)=2sin^2(pix),\at x= 3/4 is y=-2pix+1+(3pi)/2

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tangent of f(x)=2sin^2(pix),\at x= 3/4

tangent of

f (x) = 2 sin^{2} (π x), at x = \frac{3}{4}

y = - 2 π x + 1 + \frac{3 π}{2}

Solution steps

Find the tangent point:

(\frac{3}{4}, 1)

Find the slope of

f (x) = 2 sin^{2} (π x) : \frac{df ( x )}{d x} = 4 π sin (π x) cos (π x)

Compute the slope of

f (x) = 2 sin^{2} (π x)

x = \frac{3}{4} : m = - 2 π

Find the line with slope m=

- 2 π

and passing through

(\frac{3}{4}, 1) : y = - 2 π x + 1 + \frac{3 π}{2}

y = - 2 π x + 1 + \frac{3 π}{2}

\frac{d}{d t} (sin (a t))

\frac{x ^{2}}{x + 4}

\frac{ln ( x ) + 2}{x ^{2}}

n = 0 \sum \infty \frac{1}{( 1 + i ) ^{n}}

What is the tangent of f(x)=2sin^2(pix),\at x= 3/4 ?
The tangent of f(x)=2sin^2(pix),\at x= 3/4 is y=-2pix+1+(3pi)/2