What is the sum from n=0 to infinity of 1/((1+i)^n) ?

The sum from n=0 to infinity of 1/((1+i)^n) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 1/((1+i)^n)

n = 0 \sum \infty \frac{1}{( 1 + i ) ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{1}{( 1 + i ) ^{n}}

Apply Series Ratio Test:

converges

= converges

\int \frac{1}{- t ^{2} + 2 t + 3} d t

4 x^{2} + y = 4, x^{8} - y = 1

\int_{1}^{5} (x - 1)^{2} d x

\int \frac{12}{x ^{2}} d x

\frac{d}{d x} (x - \frac{1}{3} x)

What is the sum from n=0 to infinity of 1/((1+i)^n) ?
The sum from n=0 to infinity of 1/((1+i)^n) is converges