What is the integral of (2x+11)/(x^2+4x+5) ?

The integral of (2x+11)/(x^2+4x+5) is ln|x^2+4x+5|+7arctan(x+2)+C

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integral of (2x+11)/(x^2+4x+5)

\int \frac{2 x + 11}{x ^{2} + 4 x + 5} d x

ln x^{2} + 4 x + 5 + 7 arctan (x + 2) + C

Solution steps

\int \frac{2 x + 11}{x ^{2} + 4 x + 5} d x

Complete the square

x^{2} + 4 x + 5 : (x + 2)^{2} + 1

= \int \frac{2 x + 11}{( x + 2 ) ^{2} + 1} d x

Apply u-substitution

: \int \frac{2 u + 7}{u ^{2} + 1} d u

= \int \frac{2 u + 7}{u ^{2} + 1} d u

Expand

\frac{2 u + 7}{u ^{2} + 1} : \frac{2 u}{u ^{2} + 1} + \frac{7}{u ^{2} + 1}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 u}{u ^{2} + 1} d u + \int \frac{7}{u ^{2} + 1} d u

\int \frac{2 u}{u ^{2} + 1} d u = ln u^{2} + 1

\int \frac{7}{u ^{2} + 1} d u = 7 arctan (u)

= ln u^{2} + 1 + 7 arctan (u)

Substitute back

u = x + 2

= ln (x + 2)^{2} + 1 + 7 arctan (x + 2)

Expand

(x + 2)^{2} + 1 : x^{2} + 4 x + 5

= ln x^{2} + 4 x + 5 + 7 arctan (x + 2)

Add a constant to the solution

= ln x^{2} + 4 x + 5 + 7 arctan (x + 2) + C

\frac{\partial}{\partial x} (8 x^{2} y - 3)

x \to - 2 lim (- x^{2} - 4 x)

\int_{0}^{1} (2 x) d x

\frac{4 x - 9}{x - 9}

x \to 0 - lim (x^{2} + \frac{1}{x})

What is the integral of (2x+11)/(x^2+4x+5) ?
The integral of (2x+11)/(x^2+4x+5) is ln|x^2+4x+5|+7arctan(x+2)+C