What is the derivative of 4/(7x^4) ?

The derivative of 4/(7x^4) is -(16)/(7x^5)

What is the first derivative of 4/(7x^4) ?

The first derivative of 4/(7x^4) is -(16)/(7x^5)

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\frac{d}{d x} (\frac{4}{7 x ^{4}})

- \frac{16}{7 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{4}{7 x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4}{7} \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{4}{7} \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{4}{7} (- 4 x^{- 4 - 1})

Simplify

\frac{4}{7} (- 4 x^{- 4 - 1}) : - \frac{16}{7 x ^{5}}

= - \frac{16}{7 x ^{5}}

y^{^{'}} + sin (t) y = sin (t), y (0) = 7

y = x^{2} + 9 x, at x = - 8

\frac{d}{d x} (- cos (e^{x}))

\int_{1}^{6} \frac{1}{2 x + 3 + x} d x

\frac{d}{d x} (7 x (x^{3} - 8 x + 2))

What is the derivative of 4/(7x^4) ?
The derivative of 4/(7x^4) is -(16)/(7x^5)
What is the first derivative of 4/(7x^4) ?
The first derivative of 4/(7x^4) is -(16)/(7x^5)