What is the derivative of y=x^3-2x+1 ?

The derivative of y=x^3-2x+1 is 3x^2-2

What is the first derivative of y=x^3-2x+1 ?

The first derivative of y=x^3-2x+1 is 3x^2-2

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derivative of

y = x^{3} - 2 x + 1

3 x^{2} - 2

Solution steps

\frac{d}{d x} (x^{3} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 3 x^{2} - 2 + 0

Simplify

= 3 x^{2} - 2

\int \frac{1}{( 9 - x ) ^{\frac{3}{2}}} d x

\int sin (\frac{3}{4}) x cos^{2} (\frac{3}{4}) x d x

n = 1 (1 - \frac{1}{n}) \sum \infty n^{2}

\int_{2}^{4} (2 x - 3) (3 x + 1) d x

\frac{1}{y ^{2}} \cdot (y \cdot x + x^{2})

What is the derivative of y=x^3-2x+1 ?
The derivative of y=x^3-2x+1 is 3x^2-2
What is the first derivative of y=x^3-2x+1 ?
The first derivative of y=x^3-2x+1 is 3x^2-2