What is derivative of f(x)=θcos(θ) ?

The answer to derivative of f(x)=θcos(θ) is derivative of θ=0

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derivative of f(x)=θcos(θ)

derivative of

f (x) = θ cos (θ)

\frac{d}{d x} (θ) = 0

Solution steps

f (x) = θ cos (θ)

Treat

θ

θ (x)

Differentiate both sides:

0 = cos (θ) \frac{d}{d x} (θ) - sin (θ) \frac{d}{d x} (θ) θ

Isolate

\frac{d}{d x} (θ) : \frac{d}{d x} (θ) = 0

\frac{d}{d x} (θ) = 0

\frac{d}{d x} (x^{3} - 2)

\int (- 6 x) d x

f (x) = x^{2} + 4, g (x) = - x^{2} - 1, x = - 2, x = 3

f (x) = \frac{x ^{2} - 1}{2 x - 3}

\frac{d ^{2} y}{d t ^{2}} - 4 \frac{d y}{d t} - 5 y = 0

What is derivative of f(x)=θcos(θ) ?
The answer to derivative of f(x)=θcos(θ) is derivative of θ=0