What is the integral from-2 to 1 of x^{-4} ?

The integral from-2 to 1 of x^{-4} is diverges

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integral from-2 to 1 of x^{-4}

\int_{- 2}^{1} x^{- 4} d x

diverges

Solution steps

\int_{- 2}^{1} x^{- 4} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 2}^{0} x^{- 4} d x + \int_{0}^{1} x^{- 4} d x

\int_{- 2}^{0} x^{- 4} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int \frac{1}{( 1 + 5 x ) 5 x} d x

\frac{d}{d x} (\frac{3}{x ^{2}} - \frac{4}{x ^{3}})

\int_{0}^{1} \frac{ln ( x )}{5 x} d x

y = 2 (x + y) \frac{d y}{d x}

x^{\frac{5}{4}}

What is the integral from-2 to 1 of x^{-4} ?
The integral from-2 to 1 of x^{-4} is diverges