What is the solution for (x+y)dy=(x-y)dx ?

The solution for (x+y)dy=(x-y)dx is y=(-2x+sqrt(8x^2+c_{1)})/2 ,y=(-2x-sqrt(8x^2+c_{1)})/2

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(x+y)dy=(x-y)dx

(x + y) d y = (x - y) d x

y = \frac{- 2 x + 8 x ^{2} + c _{1}}{2}, y = \frac{- 2 x - 8 x ^{2} + c _{1}}{2}

Solution steps

(x + y) d y = (x - y) d x

Solve exact ODE:

y = \frac{- 2 x + 8 x ^{2} + c _{1}}{2}, y = \frac{- 2 x - 8 x ^{2} + c _{1}}{2}

y = \frac{- 2 x + 8 x ^{2} + c _{1}}{2}, y = \frac{- 2 x - 8 x ^{2} + c _{1}}{2}

f (x) = x^{4} - 13 x^{2} + 36, at x = - 2

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What is the solution for (x+y)dy=(x-y)dx ?
The solution for (x+y)dy=(x-y)dx is y=(-2x+sqrt(8x^2+c_{1)})/2 ,y=(-2x-sqrt(8x^2+c_{1)})/2