What is (\partial)/(\partial z)(x^2+y^2-z) ?

The answer to (\partial)/(\partial z)(x^2+y^2-z) is -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial z)(x^2+y^2-z)

\frac{\partial}{\partial z} (x^{2} + y^{2} - z)

- 1

Solution steps

\frac{\partial}{\partial z} (x^{2} + y^{2} - z)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x^{2}) + \frac{\partial}{\partial z} (y^{2}) - \frac{\partial}{\partial z} (z)

\frac{\partial}{\partial z} (x^{2}) = 0

\frac{\partial}{\partial z} (y^{2}) = 0

\frac{\partial}{\partial z} (z) = 1

= 0 + 0 - 1

Simplify

= - 1

\frac{d}{d x} (\frac{5 tan ( x )}{x})

\int \frac{7}{5 y - 105} d y

\frac{\partial}{\partial x} (x^{2} + x y - 25)

\int_{a}^{2 a} x d x

\int t^{2} - 4 d t

What is (\partial)/(\partial z)(x^2+y^2-z) ?
The answer to (\partial)/(\partial z)(x^2+y^2-z) is -1