What is the derivative of-0.4x^2+1000 ?

The derivative of-0.4x^2+1000 is -0.8x

What is the first derivative of-0.4x^2+1000 ?

The first derivative of-0.4x^2+1000 is -0.8x

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\frac{d}{d x} (- 0.4 x^{2} + 1000)

- 0.8 x

Solution steps

\frac{d}{d x} (- 0.4 x^{2} + 1000)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.4 x^{2}) + \frac{d}{d x} (1000)

\frac{d}{d x} (0.4 x^{2}) = 0.8 x

\frac{d}{d x} (1000) = 0

= - 0.8 x + 0

Simplify

= - 0.8 x

\frac{\partial}{\partial y} (x y - 3 x z + yz)

\int \frac{x ^{5}}{x ^{2} + 8} d x

x \to 3 lim (\frac{- x}{x - 3})

x \to 0 + lim ((tan (2 x))^{x})

\frac{d}{d x} (1 + x^{3})

What is the derivative of-0.4x^2+1000 ?
The derivative of-0.4x^2+1000 is -0.8x
What is the first derivative of-0.4x^2+1000 ?
The first derivative of-0.4x^2+1000 is -0.8x