What is the derivative of 1+sqrt(x^3) ?

The derivative of 1+sqrt(x^3) is (3sqrt(x))/2

What is the first derivative of 1+sqrt(x^3) ?

The first derivative of 1+sqrt(x^3) is (3sqrt(x))/2

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\frac{d}{d x} (1 + x^{3})

\frac{3 x}{2}

Solution steps

\frac{d}{d x} (1 + x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (x^{3})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{3}) = \frac{3 x}{2}

= 0 + \frac{3 x}{2}

Simplify

= \frac{3 x}{2}

\frac{d}{d x} (\frac{9 \cdot f ( x )}{g ( x )})

y = - x e^{x}

\int 4 tan (x) sec (3) (x) d x

f (x) = e^{3 x} cos (6 x)

\frac{d}{d x} (\frac{x ^{2} + x ^{3}}{x ^{2}})

What is the derivative of 1+sqrt(x^3) ?
The derivative of 1+sqrt(x^3) is (3sqrt(x))/2
What is the first derivative of 1+sqrt(x^3) ?
The first derivative of 1+sqrt(x^3) is (3sqrt(x))/2