What is the derivative of y=-xe^x ?

The derivative of y=-xe^x is -e^x-e^xx

What is the first derivative of y=-xe^x ?

The first derivative of y=-xe^x is -e^x-e^xx

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derivative of

y = - x e^{x}

- e^{x} - e^{x} x

Solution steps

\frac{d}{d x} (- x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= - (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= - (1 \cdot e^{x} + e^{x} x)

Simplify

= - e^{x} - e^{x} x

\int 4 tan (x) sec (3) (x) d x

f (x) = e^{3 x} cos (6 x)

\frac{d}{d x} (\frac{x ^{2} + x ^{3}}{x ^{2}})

x^{2} + 7 x - 8

\frac{d}{d x} (π cos (x))

What is the derivative of y=-xe^x ?
The derivative of y=-xe^x is -e^x-e^xx
What is the first derivative of y=-xe^x ?
The first derivative of y=-xe^x is -e^x-e^xx