What is the derivative of x*ln(x-1) ?

The derivative of x*ln(x-1) is ln(x)+1

What is the first derivative of x*ln(x-1) ?

The first derivative of x*ln(x-1) is ln(x)+1

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\frac{d}{d x} (x \cdot ln (x) - 1)

ln (x) + 1

Solution steps

\frac{d}{d x} (x ln (x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x ln (x)) - \frac{d}{d x} (1)

\frac{d}{d x} (x ln (x)) = ln (x) + 1

\frac{d}{d x} (1) = 0

= ln (x) + 1 - 0

Simplify

= ln (x) + 1

\frac{d}{d x} (\frac{tan ( x ) - 2}{sec ( x )})

(y^{2} + y x) d x - x^{2} d y = 0

\frac{\partial}{\partial x} (\frac{w}{( - 2 \cdot k \cdot \frac{T}{x} )})

\int (x^{2} + 1) sin (x) d x

What is the derivative of x*ln(x-1) ?
The derivative of x*ln(x-1) is ln(x)+1
What is the first derivative of x*ln(x-1) ?
The first derivative of x*ln(x-1) is ln(x)+1