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Popular >

(y^2+yx)dx-x^2dy=0

Solution

(y^{2} + y x) d x - x^{2} d y = 0

Solution

y = \frac{x}{- ln ( x ) + c _{1}}

Solution steps

(y^{2} + y x) d x - x^{2} d y = 0

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for (y^2+yx)dx-x^2dy=0 ?
The solution for (y^2+yx)dx-x^2dy=0 is y= x/(-ln(x)+c_{1)}