What is the tangent of y= 7/(sqrt(x)),(1,7) ?

The tangent of y= 7/(sqrt(x)),(1,7) is y=-7/2 x+21/2

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tangent of y= 7/(sqrt(x)),(1,7)

tangent of

y = \frac{7}{x}, (1, 7)

y = - \frac{7}{2} x + \frac{21}{2}

Solution steps

Find the slope of

y = \frac{7}{x} : \frac{d y}{d x} = - \frac{7}{2 x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{7}{x}

(1, 7) : m = - \frac{7}{2}

Find the line with slope m=

- \frac{7}{2}

and passing through

(1, 7) : y = - \frac{7}{2} x + \frac{21}{2}

y = - \frac{7}{2} x + \frac{21}{2}

h (t) = (t^{4} - 1)^{3} (t^{3} + 1)^{4}

\frac{d}{d x} ((6 x + 8) (4 x + 9)^{5})

\frac{d}{d x} (x e^{- \frac{1}{2} x})

\frac{\partial}{\partial x} (ln (x + 7 y + 6 z))

x \to 1 lim (\frac{3 sin ( π x ) - sin ( 3 π x )}{x ^{3}})

What is the tangent of y= 7/(sqrt(x)),(1,7) ?
The tangent of y= 7/(sqrt(x)),(1,7) is y=-7/2 x+21/2