What is the derivative of (8x+3^2) ?

The derivative of (8x+3^2) is 16(8x+3)

What is the first derivative of (8x+3^2) ?

The first derivative of (8x+3^2) is 16(8x+3)

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\frac{d}{d x} ((8 x + 3)^{2})

16 (8 x + 3)

Solution steps

\frac{d}{d x} ((8 x + 3)^{2})

Apply the chain rule:

2 (8 x + 3) \frac{d}{d x} (8 x + 3)

= 2 (8 x + 3) \frac{d}{d x} (8 x + 3)

\frac{d}{d x} (8 x + 3) = 8

= 2 (8 x + 3) \cdot 8

Simplify

= 16 (8 x + 3)

\frac{d}{d x} ((3 x^{4} + 1)^{3})

\int sec^{2} (x) tan (x) d x

\frac{d}{d x} (\frac{C ^{2} - x ^{2}}{2 x})

y^{^{''}} = x, y (- 1) = 0, y (1) = 0

\int_{0}^{\frac{π}{6}} sin^{5} (3 x) d x

What is the derivative of (8x+3^2) ?
The derivative of (8x+3^2) is 16(8x+3)
What is the first derivative of (8x+3^2) ?
The first derivative of (8x+3^2) is 16(8x+3)