What is the integral of sec^2(x)tan(x) ?

The integral of sec^2(x)tan(x) is (tan^2(x))/2+C

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integral of sec^2(x)tan(x)

\int sec^{2} (x) tan (x) d x

\frac{tan ^{2} ( x )}{2} + C

Solution steps

\int sec^{2} (x) tan (x) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = tan (x)

= \frac{tan ^{2} ( x )}{2}

Add a constant to the solution

= \frac{tan ^{2} ( x )}{2} + C

\frac{d}{d x} (\frac{C ^{2} - x ^{2}}{2 x})

y^{^{''}} = x, y (- 1) = 0, y (1) = 0

\int_{0}^{\frac{π}{6}} sin^{5} (3 x) d x

\frac{d}{d x} (- 4 e^{3 x})

\int \frac{x ^{2}}{256 - 64 x ^{2}} d x

What is the integral of sec^2(x)tan(x) ?
The integral of sec^2(x)tan(x) is (tan^2(x))/2+C