What is the limit as x approaches-4+of 1/((x+4)^2) ?

The limit as x approaches-4+of 1/((x+4)^2) is infinity

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limit as x approaches-4+of 1/((x+4)^2)

x \to - 4 + lim (\frac{1}{( x + 4 ) ^{2}})

\infty

Solution steps

x \to - 4 + lim (\frac{1}{( x + 4 ) ^{2}})

For

x

approaching

- 4

from the right

, x > - 4 \Rightarrow (x + 4)^{2} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int \frac{arctan ( 2 x )}{1 + 4 x ^{2}} d x

\frac{1}{12 x ^{2}}, x, \frac{x}{10}

16 y^{^{''''}} + 24 y^{^{''}} + 9 y = 0

\frac{\partial}{\partial x} (x^{3} - 3 y^{2})

x \to 4 lim (\frac{1}{x})

What is the limit as x approaches-4+of 1/((x+4)^2) ?
The limit as x approaches-4+of 1/((x+4)^2) is infinity