What is integral from 1 to 2 of f(x) ?

The answer to integral from 1 to 2 of f(x) is (3f)/2

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integral from 1 to 2 of f(x)

\int_{1}^{2} f (x) d x

\frac{3 f}{2}

Solution steps

\int_{1}^{2} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{1}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{2}

= f [\frac{x ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= f \frac{3}{2}

Simplify

= \frac{3 f}{2}

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What is integral from 1 to 2 of f(x) ?
The answer to integral from 1 to 2 of f(x) is (3f)/2