What is the solution for x^2(dy)/(dx)-2xy=5y^4 ?

The solution for x^2(dy)/(dx)-2xy=5y^4 is y=(x^2)/(\sqrt[3]{-3x^5+c_{1)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2(dy)/(dx)-2xy=5y^4

x^{2} \frac{d y}{d x} - 2 x y = 5 y^{4}

Solution steps

x^{2} \frac{d y}{d x} - 2 x y = 5 y^{4}

Solve Bernoulli ODE:

\int_{- 2}^{2} (x + 2) 4 - x^{2} d x

y^{^{''}} + 12 y^{^{'}} + 40 y = 0

\int - 2 e^{- 2 x} d x

y^{^{''}} + 16 y = - 8 sin (4 t)

\frac{4}{x ^{5}}

What is the solution for x^2(dy)/(dx)-2xy=5y^4 ?
The solution for x^2(dy)/(dx)-2xy=5y^4 is y=(x^2)/(\sqrt[3]{-3x^5+c_{1)}}