What is the derivative of \sqrt[3]{2x-3} ?

The derivative of \sqrt[3]{2x-3} is 2/(3(2x-3)^{2/3)}

What is the first derivative of \sqrt[3]{2x-3} ?

The first derivative of \sqrt[3]{2x-3} is 2/(3(2x-3)^{2/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{2}{3 ( 2 x - 3 ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( 2 x - 3 ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x - 3)

= \frac{1}{3 ( 2 x - 3 ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x - 3)

\frac{d}{d x} (2 x - 3) = 2

= \frac{1}{3 ( 2 x - 3 ) ^{\frac{2}{3}}} \cdot 2

Simplify

\frac{1}{3 ( 2 x - 3 ) ^{\frac{2}{3}}} \cdot 2 : \frac{2}{3 ( 2 x - 3 ) ^{\frac{2}{3}}}

= \frac{2}{3 ( 2 x - 3 ) ^{\frac{2}{3}}}

\int \frac{x + 3 x ^{2}}{y ^{2}} d x

\int \frac{1}{1 - cos ( x )} d x

\frac{\partial}{\partial u} (u + v^{2})

\int_{0}^{5} (x + 1) d x

\int (θ^{2} - csc^{2} (θ)) d θ

What is the derivative of \sqrt[3]{2x-3} ?
The derivative of \sqrt[3]{2x-3} is 2/(3(2x-3)^{2/3)}
What is the first derivative of \sqrt[3]{2x-3} ?
The first derivative of \sqrt[3]{2x-3} is 2/(3(2x-3)^{2/3)}