What is the integral of (8-4x)e^{2x} ?

The integral of (8-4x)e^{2x} is -2e^{2x}x+5e^{2x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (8-4x)e^{2x}

\int (8 - 4 x) e^{2 x} d x

- 2 e^{2 x} x + 5 e^{2 x} + C

Solution steps

\int (8 - 4 x) e^{2 x} d x

Apply Integration By Parts

: 2 e^{2 x} (- x + 2) - \int - 2 e^{2 x} d x

= 2 e^{2 x} (- x + 2) - \int - 2 e^{2 x} d x

\int - 2 e^{2 x} d x = - e^{2 x}

= 2 e^{2 x} (- x + 2) - (- e^{2 x})

Simplify

2 e^{2 x} (- x + 2) - (- e^{2 x}) : - 2 e^{2 x} x + 5 e^{2 x}

= - 2 e^{2 x} x + 5 e^{2 x}

Add a constant to the solution

= - 2 e^{2 x} x + 5 e^{2 x} + C

\frac{d y}{d x} - 4 tan (2 x) y = sin (2 x)

x \to 0 - lim (e^{c s c (x)})

n = 1 \sum \infty \frac{e ^{\frac{7}{n}}}{n}

\frac{d}{d x} (p x + b)

x \to 1 + lim (\frac{4}{1 - x})

What is the integral of (8-4x)e^{2x} ?
The integral of (8-4x)e^{2x} is -2e^{2x}x+5e^{2x}+C