en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2^{2x}

Solution

\int 2^{2 x} d x

Solution

\frac{2 ^{2 x - 1}}{ln ( 2 )} + C

Solution steps

\int 2^{2 x} d x

Simplify

2^{2 x} : 4^{x}

= \int 4^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{4 ^{x}}{ln ( 4 )}

Simplify

\frac{4 ^{x}}{ln ( 4 )} : \frac{2 ^{2 x - 1}}{ln ( 2 )}

= \frac{2 ^{2 x - 1}}{ln ( 2 )}

Add a constant to the solution

= \frac{2 ^{2 x - 1}}{ln ( 2 )} + C

Popular Examples

derivative of-(24/(x^4))

\frac{d}{d x} (- \frac{24}{x ^{4}})

area y=x(x^2-10x+30),y=x^2 area

y = x (x^{2} - 10 x + 30), y = x^{2}

integral of xe^{-125x}

\int x e^{- 125 x} d x

area x^2+x+23,2x^2+3 area

x^{2} + x + 23, 2 x^{2} + 3

sum from n=5 to infinity of 1/(27^n)

n = 5 \sum \infty \frac{1}{2 7 ^{n}}

Frequently Asked Questions (FAQ)

What is the integral of 2^{2x} ?
The integral of 2^{2x} is (2^{2x-1})/(ln(2))+C