What is the solution for (dy)/(dx)=((y^2+4))/(2xy) ?

The solution for (dy)/(dx)=((y^2+4))/(2xy) is y=sqrt(c_{1)x-4},y=-sqrt(c_{1)x-4}

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(dy)/(dx)=((y^2+4))/(2xy)

\frac{d y}{d x} = \frac{( y ^{2} + 4 )}{2 x y}

y = c_{1} x - 4, y = - c_{1} x - 4

Solution steps

\frac{d y}{d x} = \frac{( y ^{2} + 4 )}{2 x y}

Solve separable ODE:

y = c_{1} x - 4, y = - c_{1} x - 4

y = c_{1} x - 4, y = - c_{1} x - 4

\frac{d y}{d x} = \frac{cos ( 8 x )}{cos ( 4 y )}

\frac{s + 3}{s + 5}

\int e^{i 7 x} cos (3 x) d x

\int_{- 2}^{1} (2 x^{2} + 3) d x

\frac{d}{d x} (1 + cos (x))

What is the solution for (dy)/(dx)=((y^2+4))/(2xy) ?
The solution for (dy)/(dx)=((y^2+4))/(2xy) is y=sqrt(c_{1)x-4},y=-sqrt(c_{1)x-4}