What is the derivative of 1+cos(x) ?

The derivative of 1+cos(x) is -sin(x)

What is the first derivative of 1+cos(x) ?

The first derivative of 1+cos(x) is -sin(x)

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\frac{d}{d x} (1 + cos (x))

- sin (x)

Solution steps

\frac{d}{d x} (1 + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cos (x)) = - sin (x)

= 0 - sin (x)

Simplify

= - sin (x)

\int 4 x + 3 d x

\frac{d}{d x} (- sin (2 x) - 2 cos (x))

\frac{d}{d x} (\frac{4 x ^{2} + 6 x + 6}{x})

\int x^{3} \cdot ln (2 x) d x

\frac{s + 5}{s ( s ^{2} + 5 s + 6 )}

What is the derivative of 1+cos(x) ?
The derivative of 1+cos(x) is -sin(x)
What is the first derivative of 1+cos(x) ?
The first derivative of 1+cos(x) is -sin(x)