What is the derivative of ln(2x+1-x^2) ?

The derivative of ln(2x+1-x^2) is 2/(2x+1)-2x

What is the first derivative of ln(2x+1-x^2) ?

The first derivative of ln(2x+1-x^2) is 2/(2x+1)-2x

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\frac{d}{d x} (ln (2 x + 1) - x^{2})

\frac{2}{2 x + 1} - 2 x

Solution steps

\frac{d}{d x} (ln (2 x + 1) - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (2 x + 1)) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (ln (2 x + 1)) = \frac{2}{2 x + 1}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{2}{2 x + 1} - 2 x

f (x) = csc^{2} (x)

\int_{1}^{2} \frac{11}{x ^{3} + 4 x} d x

2 cos^{2} (t)

\int x^{4} e^{x^{5} + 2} d x

\int_{- 4}^{- 2} \frac{1}{x ^{3}} d x

What is the derivative of ln(2x+1-x^2) ?
The derivative of ln(2x+1-x^2) is 2/(2x+1)-2x
What is the first derivative of ln(2x+1-x^2) ?
The first derivative of ln(2x+1-x^2) is 2/(2x+1)-2x