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Popular >

(-ln(2x))^'

Solution

(- ln (2 x))^{^{'}}

Solution

- \frac{1}{x}

Solution steps

(- ln (2 x))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - (ln (2 x))^{^{'}}

Apply the chain rule:

\frac{1}{2 x} (2 x)^{'}

= \frac{1}{2 x} (2 x)^{'}

(2 x)^{'} = 2

= - \frac{1}{2 x} \cdot 2

Simplify

- \frac{1}{2 x} \cdot 2 : - \frac{1}{x}

= - \frac{1}{x}

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Frequently Asked Questions (FAQ)

What is the (-ln(2x))^' ?
The (-ln(2x))^' is -1/x
What is the first (-ln(2x))^' ?
The first (-ln(2x))^' is -1/x