What is the integral of 6/(sqrt(x))+6sqrt(x) ?

The integral of 6/(sqrt(x))+6sqrt(x) is 12sqrt(x)+4x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 6/(sqrt(x))+6sqrt(x)

\int \frac{6}{x} + 6 x d x

12 x + 4 x^{\frac{3}{2}} + C

Solution steps

\int \frac{6}{x} + 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6}{x} d x + \int 6 x d x

\int \frac{6}{x} d x = 12 x

\int 6 x d x = 4 x^{\frac{3}{2}}

= 12 x + 4 x^{\frac{3}{2}}

Add a constant to the solution

= 12 x + 4 x^{\frac{3}{2}} + C

(- 27 sin (3 x) - 27 x cos (3 x))^{^{'}}

f (x) = \frac{2 x}{x ^{2} + 1}, at x = - 1, - 1

\frac{2 e ^{- s}}{( s + \frac{1}{5} )}

y^{^{''}} - 5 y^{^{'}} - 14 y = 0

\frac{\partial}{\partial x} (6)

What is the integral of 6/(sqrt(x))+6sqrt(x) ?
The integral of 6/(sqrt(x))+6sqrt(x) is 12sqrt(x)+4x^{3/2}+C