What is the limit as x approaches 0 of (3x+1)^{1/x} ?

The limit as x approaches 0 of (3x+1)^{1/x} is e^3

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limit as x approaches 0 of (3x+1)^{1/x}

x \to 0 lim ((3 x + 1)^{\frac{1}{x}})

e^{3}

Decimal Notation

20.08553 \dots

Solution steps

x \to 0 lim ((3 x + 1)^{\frac{1}{x}})

Apply exponent rules

= x \to 0 lim (e^{\frac{1}{x} l n (3 x + 1)})

Apply the Limit Chain Rule:

e^{3}

= e^{3}

\frac{\partial}{\partial y} (x y sin (x))

\frac{\partial}{\partial x} (y^{4} - 4 x y)

\int ln (1 - x^{2}) d x

x \to - 7 + lim (x + 7)

\frac{\partial}{\partial x} (12 x^{2} - 9 x y + 16 y^{2})

What is the limit as x approaches 0 of (3x+1)^{1/x} ?
The limit as x approaches 0 of (3x+1)^{1/x} is e^3