What is the solution for y^{''}+5y^'+6y=6 ?

The solution for y^{''}+5y^'+6y=6 is y=c_{1}e^{-2t}+c_{2}e^{-3t}+1

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y^{''}+5y^'+6y=6

y^{^{''}} + 5 y^{^{'}} + 6 y = 6

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + 1

Solution steps

y^{''} (t) + 5 y^{'} (t) + 6 y = 6

Solve linear ODE:

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + 1

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + 1

\frac{d}{d t} (t^{2})

y = e^{- s i n (x)}

q^{^{'}} + \frac{q}{20 + t} = 1

y^{^{'}} = x^{2} \frac{1}{y}

y = x^{2 x}

What is the solution for y^{''}+5y^'+6y=6 ?
The solution for y^{''}+5y^'+6y=6 is y=c_{1}e^{-2t}+c_{2}e^{-3t}+1