What is the derivative of e^r+r^e ?

The derivative of e^r+r^e is e^r+er^{e-1}

What is the first derivative of e^r+r^e ?

The first derivative of e^r+r^e is e^r+er^{e-1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

e^{r} + r^{e}

e^{r} + e r^{e - 1}

Solution steps

\frac{d}{d r} (e^{r} + r^{e})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (e^{r}) + \frac{d}{d r} (r^{e})

\frac{d}{d r} (e^{r}) = e^{r}

\frac{d}{d r} (r^{e}) = e r^{e - 1}

= e^{r} + e r^{e - 1}

f (x) = \frac{2 x}{3 - tan ( x )}

\frac{\partial}{\partial x} (sin (8 x - 9 y))

\frac{x}{2} + 3

\frac{\partial}{\partial x} (ln (x + 2 y + 6 z))

\frac{d}{d x} (A e^{- \frac{3}{2} x} + B e^{3 x} + C x e^{3 x} + d x^{2} e^{3 x})

What is the derivative of e^r+r^e ?
The derivative of e^r+r^e is e^r+er^{e-1}
What is the first derivative of e^r+r^e ?
The first derivative of e^r+r^e is e^r+er^{e-1}