What is maclaurin 1/(\sqrt[3]{2x+1)} ?

The answer to maclaurin 1/(\sqrt[3]{2x+1)} is 1-2/3 x+8/9 x^2-112/81 x^3+560/243 x^4+\ldots

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maclaurin 1/(\sqrt[3]{2x+1)}

maclaurin

1 - \frac{2}{3} x + \frac{8}{9} x^{2} - \frac{112}{81} x^{3} + \frac{560}{243} x^{4} + \dots

Solution steps

Apply the Maclaurin Formula

Evaluate Derivatives

= 1 + \frac{- \frac{2}{3}}{1 !} x + \frac{\frac{16}{9}}{2 !} x^{2} + \frac{- \frac{224}{27}}{3 !} x^{3} + \frac{\frac{4480}{81}}{4 !} x^{4} + \dots

Refine

= 1 - \frac{2}{3} x + \frac{8}{9} x^{2} - \frac{112}{81} x^{3} + \frac{560}{243} x^{4} + \dots

\frac{d ^{2}}{d x ^{2}} (e^{5 x})

\frac{\partial}{\partial x} (10 x y)

\int sin (2 x) cos (x) d x

f (x) = x^{2} + 8

y = 2 x^{2} e^{x} + 4 x^{3}

What is maclaurin 1/(\sqrt[3]{2x+1)} ?
The answer to maclaurin 1/(\sqrt[3]{2x+1)} is 1-2/3 x+8/9 x^2-112/81 x^3+560/243 x^4+\ldots