What is the derivative of f(x)=sqrt(x^2+8) ?

The derivative of f(x)=sqrt(x^2+8) is x/(sqrt(x^2+8))

What is the first derivative of f(x)=sqrt(x^2+8) ?

The first derivative of f(x)=sqrt(x^2+8) is x/(sqrt(x^2+8))

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derivative of

f (x) = x^{2} + 8

\frac{x}{x ^{2} + 8}

Solution steps

\frac{d}{d x} (x^{2} + 8)

Apply the chain rule:

\frac{1}{2 x ^{2} + 8} \frac{d}{d x} (x^{2} + 8)

= \frac{1}{2 x ^{2} + 8} \frac{d}{d x} (x^{2} + 8)

\frac{d}{d x} (x^{2} + 8) = 2 x

= \frac{1}{2 x ^{2} + 8} \cdot 2 x

Simplify

\frac{1}{2 x ^{2} + 8} \cdot 2 x : \frac{x}{x ^{2} + 8}

= \frac{x}{x ^{2} + 8}

y = 2 x^{2} e^{x} + 4 x^{3}

x \to 0 lim ((1 - 5 x)^{\frac{7}{x}})

\frac{x}{x + 13}

x \to - 5 lim (\frac{x ^{2} + 6}{x + 2})

x \to 1 lim (\frac{x}{x ^{2} - 2 x + 1})

What is the derivative of f(x)=sqrt(x^2+8) ?
The derivative of f(x)=sqrt(x^2+8) is x/(sqrt(x^2+8))
What is the first derivative of f(x)=sqrt(x^2+8) ?
The first derivative of f(x)=sqrt(x^2+8) is x/(sqrt(x^2+8))