What is the limit as x approaches 1 of x/(x^2-2x+1) ?

The limit as x approaches 1 of x/(x^2-2x+1) is infinity

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limit as x approaches 1 of x/(x^2-2x+1)

x \to 1 lim (\frac{x}{x ^{2} - 2 x + 1})

\infty

Solution steps

x \to 1 lim (\frac{x}{x ^{2} - 2 x + 1})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 1 - lim (\frac{x}{x ^{2} - 2 x + 1}) = \infty

x \to 1 + lim (\frac{x}{x ^{2} - 2 x + 1}) = \infty

= \infty

\frac{d}{d x} (\frac{6}{5} \cdot cos (x))

\frac{a}{2 s ^{3}}

tan (x e^{x})

x \to 0 lim (x^{2} + 5 x)

f (x) = x^{2} + 6 x + 1

What is the limit as x approaches 1 of x/(x^2-2x+1) ?
The limit as x approaches 1 of x/(x^2-2x+1) is infinity