What is the integral of (e^t+2t+ln(t)) ?

The integral of (e^t+2t+ln(t)) is e^t+t^2+tln(t)-t+C

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integral of (e^t+2t+ln(t))

\int (e^{t} + 2 t + ln (t)) d t

e^{t} + t^{2} + t ln (t) - t + C

Solution steps

\int e^{t} + 2 t + ln (t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{t} d t + \int 2 t d t + \int ln (t) d t

\int e^{t} d t = e^{t}

\int 2 t d t = t^{2}

\int ln (t) d t = t ln (t) - t

= e^{t} + t^{2} + t ln (t) - t

Add a constant to the solution

= e^{t} + t^{2} + t ln (t) - t + C

y^{^{'}} = 5 y (1 - \frac{y}{7})

\frac{d}{d s} (1)

\frac{d}{d x} ((- 2 x - 3)^{5} (3 x + 1)^{3})

n = 2 \sum \infty ln (n)

t \to 0 lim (ln (t))

What is the integral of (e^t+2t+ln(t)) ?
The integral of (e^t+2t+ln(t)) is e^t+t^2+tln(t)-t+C