What is the sum from n=2 to infinity of ln(n) ?

The sum from n=2 to infinity of ln(n) is diverges

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sum from n=2 to infinity of ln(n)

n = 2 \sum \infty ln (n)

diverges

Solution steps

n = 2 \sum \infty ln (n)

Apply Series Divergence Test:

diverges

= diverges

t \to 0 lim (ln (t))

\int cot (t) sin^{2} (t) - 25 d t

\int 1 - sin^{2} (x) d x

\frac{d}{d x} ((x - 4)^{2})

\frac{d}{d x} (ln (2 x - x))

What is the sum from n=2 to infinity of ln(n) ?
The sum from n=2 to infinity of ln(n) is diverges