What is the derivative of (x-4^2) ?

The derivative of (x-4^2) is 2(x-4)

What is the first derivative of (x-4^2) ?

The first derivative of (x-4^2) is 2(x-4)

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\frac{d}{d x} ((x - 4)^{2})

2 (x - 4)

Solution steps

\frac{d}{d x} ((x - 4)^{2})

Apply the chain rule:

2 (x - 4) \frac{d}{d x} (x - 4)

= 2 (x - 4) \frac{d}{d x} (x - 4)

\frac{d}{d x} (x - 4) = 1

= 2 (x - 4) \cdot 1

Simplify

= 2 (x - 4)

\frac{d}{d x} (ln (2 x - x))

\int x^{3} + x^{2} (3 x^{2} + 2 x) d x

\int (\frac{5}{x} + \frac{15}{x ^{6}}) d x

t - 4

(x + y) \cdot y^{^{'}} = 2 \cdot x + 2 \cdot y - 3

What is the derivative of (x-4^2) ?
The derivative of (x-4^2) is 2(x-4)
What is the first derivative of (x-4^2) ?
The first derivative of (x-4^2) is 2(x-4)