What is the derivative of 1/x+x^2-2 ?

The derivative of 1/x+x^2-2 is 2x-1/(x^2)

What is the first derivative of 1/x+x^2-2 ?

The first derivative of 1/x+x^2-2 is 2x-1/(x^2)

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\frac{d}{d x} (\frac{1}{x} + x^{2} - 2)

2 x - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x} + x^{2} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2)

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2) = 0

= - \frac{1}{x ^{2}} + 2 x - 0

Simplify

= 2 x - \frac{1}{x ^{2}}

\frac{x ^{2} + 2 x + 1}{x ^{2} - 2 x + 1}

- \frac{7}{1 + x ^{2}}

n = 1 \sum \infty \frac{n}{2 n ^{3} + 3}

\frac{4 x + 5}{4 x - 5}

\frac{1}{( s ^{2} )}

What is the derivative of 1/x+x^2-2 ?
The derivative of 1/x+x^2-2 is 2x-1/(x^2)
What is the first derivative of 1/x+x^2-2 ?
The first derivative of 1/x+x^2-2 is 2x-1/(x^2)