What is the solution for (y^{''})/y =3 ?

The solution for (y^{''})/y =3 is y=c_{1}e^{sqrt(3)t}+c_{2}e^{-sqrt(3)t}

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(y^{''})/y =3

\frac{y ^{^{''}}}{y} = 3

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

Solution steps

\frac{y ^{''} ( t )}{y} = 3

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

y = c_{1} e^{3 t} + c_{2} e^{- 3 t}

(14 - 12 y + e - 3 x) d x - 4 d y = 0

n = 1 \sum \infty \frac{e ^{\frac{1}{n}}}{n}

\frac{1}{( s + 2 ) ^{2} + 4}

\int \frac{3 x - 4}{x ^{2} - x - 2} d x

\int \frac{5 x ^{2} + 9 x + 5}{( x ^{2} + 1 ) ^{2}} d x

What is the solution for (y^{''})/y =3 ?
The solution for (y^{''})/y =3 is y=c_{1}e^{sqrt(3)t}+c_{2}e^{-sqrt(3)t}