What is the tangent of f(x)=-2xcos(x),(pi,2pi) ?

The tangent of f(x)=-2xcos(x),(pi,2pi) is y=2x

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tangent of f(x)=-2xcos(x),(pi,2pi)

tangent of

f (x) = - 2 x cos (x), (π, 2 π)

y = 2 x

Solution steps

Find the slope of

f (x) = - 2 x cos (x) : \frac{df ( x )}{d x} = - 2 (cos (x) - x sin (x))

Compute the slope of

f (x) = - 2 x cos (x)

(π, 2 π) : m = 2

Find the line with slope m=

2

and passing through

(π, 2 π) : y = 2 x

y = 2 x

n = 0 \sum \infty n! 2^{n}

5 x y (\frac{d y}{d x}) = 4

x \to 1 lim (ln (8 x) + e^{x})

\frac{d}{d x} (5 e^{- 0.5 x} + 100)

\int \frac{2 ^{18 x}}{4} d x

What is the tangent of f(x)=-2xcos(x),(pi,2pi) ?
The tangent of f(x)=-2xcos(x),(pi,2pi) is y=2x