What is the derivative of y=3cos(2x) ?

The derivative of y=3cos(2x) is -6sin(2x)

What is the first derivative of y=3cos(2x) ?

The first derivative of y=3cos(2x) is -6sin(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 3 cos (2 x)

- 6 sin (2 x)

Solution steps

\frac{d}{d x} (3 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 3 (- sin (2 x) \cdot 2)

Simplify

= - 6 sin (2 x)

\int_{1}^{4} (x - 3)^{2} d x

x y^{^{'}} + y = 8 x y^{2}, y (1) = 3

\frac{d}{d x} (cos (2 \cdot x))

y = 8 x, (4, 16)

\frac{\partial}{\partial x} ((75 - x) \frac{1}{3} π x^{2})

What is the derivative of y=3cos(2x) ?
The derivative of y=3cos(2x) is -6sin(2x)
What is the first derivative of y=3cos(2x) ?
The first derivative of y=3cos(2x) is -6sin(2x)