What is the tangent of f(x)= 4/(5x+1),\at x=-1 ?

The tangent of f(x)= 4/(5x+1),\at x=-1 is y=-5/4 x-9/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 4/(5x+1),\at x=-1

tangent of

f (x) = \frac{4}{5 x + 1}, at x = - 1

y = - \frac{5}{4} x - \frac{9}{4}

Solution steps

Find the tangent point:

(- 1, - 1)

Find the slope of

f (x) = \frac{4}{5 x + 1} : \frac{df ( x )}{d x} = - \frac{20}{( 5 x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{4}{5 x + 1}

x = - 1 : m = - \frac{5}{4}

Find the line with slope m=

- \frac{5}{4}

and passing through

(- 1, - 1) : y = - \frac{5}{4} x - \frac{9}{4}

y = - \frac{5}{4} x - \frac{9}{4}

(ln (sin (x)))^{^{'}}

\frac{\partial}{\partial x} ((1 x, 3 y, 4 z) \cdot (1, 2, 3))

\int_{3}^{6} (3 x - x)^{2} d x

\int (x^{20} - 5 x^{4})^{3} (x^{19} - x^{3}) d x

f (x) = \frac{6}{x}, at x = 4

What is the tangent of f(x)= 4/(5x+1),\at x=-1 ?
The tangent of f(x)= 4/(5x+1),\at x=-1 is y=-5/4 x-9/4