What is the solution for (dy)/(dt)= 9/40-y/(200),y(0)=90 ?

The solution for (dy)/(dt)= 9/40-y/(200),y(0)=90 is y=45+(45)/(e^{t/(200))}

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(dy)/(dt)= 9/40-y/(200),y(0)=90

\frac{d y}{d t} = \frac{9}{40} - \frac{y}{200}, y (0) = 90

y = 45 + \frac{45}{e ^{\frac{t}{200}}}

Solution steps

\frac{d y}{d t} = \frac{9}{40} - \frac{y}{200}

Solve linear ODE:

y = 45 + \frac{45}{e ^{\frac{t}{200}}}

y = 45 + \frac{45}{e ^{\frac{t}{200}}}

\frac{d}{d t} (7 cos (t))

y = ln (1 + sin (x))

\int \frac{sin ( x )}{7 + cos ^{2} ( x )} d x

\frac{d}{d x} (4 x^{4} - 32 x^{3} + 89 x^{2} - 95 x + 29)

What is the solution for (dy)/(dt)= 9/40-y/(200),y(0)=90 ?
The solution for (dy)/(dt)= 9/40-y/(200),y(0)=90 is y=45+(45)/(e^{t/(200))}