What is the integral of cos^8(x)sin(x) ?

The integral of cos^8(x)sin(x) is -(cos^9(x))/9+C

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integral of cos^8(x)sin(x)

\int cos^{8} (x) sin (x) d x

- \frac{cos ^{9} ( x )}{9} + C

Solution steps

\int cos^{8} (x) sin (x) d x

Apply u-substitution

: \int - u^{8} d u

= \int - u^{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{8} d u

Apply the Power Rule

: \frac{u ^{9}}{9}

= - \frac{u ^{9}}{9}

Substitute back

u = cos (x)

= - \frac{cos ^{9} ( x )}{9}

Add a constant to the solution

= - \frac{cos ^{9} ( x )}{9} + C

\int cos (5 t) d t

x \to 1 - lim (4 x)

y^{^{'}} = 0.05 ln (\frac{2000}{y}) y

\frac{s}{s + 8}

\frac{\partial}{\partial x} ((x + y) \cdot e^{x + 2 y})

What is the integral of cos^8(x)sin(x) ?
The integral of cos^8(x)sin(x) is -(cos^9(x))/9+C