en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(2y)/t+t

Solution

y^{^{'}} = \frac{2 y}{t} + t

Solution

y = ln (t) t^{2} + c_{1} t^{2}

Solution steps

y^{'} (t) = \frac{2 y}{t} + t

Solve linear ODE:

y = ln (t) t^{2} + c_{1} t^{2}

y = ln (t) t^{2} + c_{1} t^{2}

Popular Examples

derivative of x^{-1}derivative of

x^{- 1}

integral of (1-u)/(1+u)

\int \frac{1 - u}{1 + u} d u

limit as x approaches 0 of 2sin(x)-1

x \to 0 lim (2 sin (x) - 1)

integral of ((ln(x))/(x^2))

\int (\frac{ln ( x )}{x ^{2}}) d x

d/(dz)(sqrt(1-z^2))

\frac{d}{d z} (1 - z^{2})

Frequently Asked Questions (FAQ)

What is the solution for y^'=(2y)/t+t ?
The solution for y^'=(2y)/t+t is y=ln(t)t^2+c_{1}t^2