What is the limit as x approaches 0 of 2sin(x)-1 ?

The limit as x approaches 0 of 2sin(x)-1 is -1

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limit as x approaches 0 of 2sin(x)-1

x \to 0 lim (2 sin (x) - 1)

- 1

Solution steps

x \to 0 lim (2 sin (x) - 1)

Plug in the value

x = 0

= 2 sin (0) - 1

Simplify

2 sin (0) - 1 : - 1

= - 1

\int (\frac{ln ( x )}{x ^{2}}) d x

\frac{d}{d z} (1 - z^{2})

\int_{- 1}^{2} \frac{x ^{3}}{3} d x

\int x e^{- 9 x} d x

(- 2 x y^{2} + 1 y) d x + (- 2 x^{2} y + 1 x) d y = 0

What is the limit as x approaches 0 of 2sin(x)-1 ?
The limit as x approaches 0 of 2sin(x)-1 is -1