What is the tangent of f(x)=sqrt(2x),(8,4) ?

The tangent of f(x)=sqrt(2x),(8,4) is y= 1/4 x+2

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tangent of f(x)=sqrt(2x),(8,4)

tangent of

f (x) = 2 x, (8, 4)

y = \frac{1}{4} x + 2

Solution steps

Find the slope of

f (x) = 2 x : \frac{df ( x )}{d x} = \frac{1}{2 x}

Compute the slope of

f (x) = 2 x

(8, 4) : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(8, 4) : y = \frac{1}{4} x + 2

y = \frac{1}{4} x + 2

\int y^{2} e^{x y} + cos (x) d x

\frac{\partial}{\partial y} (1 - y^{3})

\frac{d y}{d x} = \frac{1 + x}{y}

x \to 0 lim (\frac{7}{x ^{2} + x} - \frac{7}{x})

\frac{\partial}{\partial x} (\frac{x y}{x + 1})

What is the tangent of f(x)=sqrt(2x),(8,4) ?
The tangent of f(x)=sqrt(2x),(8,4) is y= 1/4 x+2