What is the derivative of y=60x^{-9} ?

The derivative of y=60x^{-9} is -(540)/(x^{10)}

What is the first derivative of y=60x^{-9} ?

The first derivative of y=60x^{-9} is -(540)/(x^{10)}

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derivative of

y = 60 x^{- 9}

- \frac{540}{x ^{10}}

Solution steps

\frac{d}{d x} (60 x^{- 9})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 60 \frac{d}{d x} (x^{- 9})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 60 (- 9 x^{- 9 - 1})

Simplify

60 (- 9 x^{- 9 - 1}) : - \frac{540}{x ^{10}}

= - \frac{540}{x ^{10}}

\frac{d}{d x} ((\frac{2 y + 3}{4 x + 5})^{2})

f (x) = \frac{4 x}{x - 5}, (7, 14)

\frac{d u}{d x}

4 y^{^{''}} + y = 0

n = 0 \sum \infty n^{2} + n

What is the derivative of y=60x^{-9} ?
The derivative of y=60x^{-9} is -(540)/(x^{10)}
What is the first derivative of y=60x^{-9} ?
The first derivative of y=60x^{-9} is -(540)/(x^{10)}