What is the integral of (6/(sqrt(x))) ?

The integral of (6/(sqrt(x))) is 12sqrt(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (6/(sqrt(x)))

\int (\frac{6}{x}) d x

12 x + C

Solution steps

\int \frac{6}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 6 \cdot 2 x^{\frac{1}{2}}

Simplify

6 \cdot 2 x^{\frac{1}{2}} : 12 x

= 12 x

Add a constant to the solution

= 12 x + C

\frac{1}{q + k e ^{q}}

\frac{\partial}{\partial y} (4 x^{\frac{y}{z}})

y^{^{''}} + y = 3 e^{- 8 x}

\int_{0}^{4} x^{3} 7 - x^{2} d x

f (x) = x^{3} - \frac{2}{x ^{2}} + 2, (1, 3)

What is the integral of (6/(sqrt(x))) ?
The integral of (6/(sqrt(x))) is 12sqrt(x)+C